Vedic Maths : Nikhilam Navatashcaramam Dashatah


Vedic Maths : Nikhilam Navatashcaramam Dashatah

All from 9 and the last from 10

निखिलं नवतः चरमं दशतः

Any number can be expressed as : N = x + k, Where x is 10 ^ n and k is remainder if you divide N with 10 ^ n. Here N, n, k are integer. k can be negative also. 

Here are the examples: 

N

x

k

n

N = (x = 10 ^ n)  + k

9

10

-1

1

10 ^ 1 - 1

7

10

-3

1

10 ^ 1 – 3

6

10

-4

1

10 ^ 1 – 4

8

10

-2

1

10 ^ 1 – 2

5

10

-5

1

10 ^ 1 – 5

89

100

-11

2

10 ^ 2 – 11

95

100

-5

2

10 ^ 2 – 5

88

100

-12

2

10 ^ 2 – 12

91

100

-9

2

10 ^ 2 – 9

99

100

-1

2

10 ^ 2 – 1

97

100

-3

2

10 ^ 2 -3

888

1000

-112

3

10 ^ 3 – 112

998

1000

-2

3

10 ^ 3 – 2

991

1000

-9

3

10 ^ 3 – 9

997

1000

-3

3

10 ^ 3 – 3

9999

10000

-1

4

10 ^ 4 – 1

99979

100000

-21

5

10 ^ 5 – 21

99999

100000

-1

5

10 ^ 5 – 1

9999999998

10000000000

-2

10

10 ^ 10 – 2

16

10

+6

1

10 ^ 1 + 6

11

10

+1

1

10 ^ 1 + 1

12

10

+2

1

10 ^ 1 + 2

13

10

+3

1

10 ^ 1 + 3

15

10

+5

1

10 ^ 1 + 5

16

10

+6

1

10 ^ 1 + 6

17

10

+7

1

10 ^ 1 + 7

18

10

+8

1

10 ^ 1 + 8

108

100

+8

2

10 ^ 2 + 8

111

100

+11

2

10 ^ 2 + 11

109

100

+9

2

10 ^ 2 + 9

1005

1000

+5

3

10 ^ 3 + 5

1009

1000

+9

3

10 ^ 3 + 9

1016

1000

+16

3

10 ^ 3 + 16

1006

1000

+6

3

10 ^ 3 + 6

1026

1000

+26

3

10 ^ 3 + 26

10006

10000

+6

4

10 ^ 4 + 6


Now let's have two number A and B where k is a and b respectively
A = x + a
B = x + b
A * B = (x + a) * (x + b)
= x ^ 2 + x ( a + b ) + ab
= x ( x + a + b) + ab

Here, a or b or both can be negative or positive. 

Example: 108 * 97 = (100 + 8 ) * (100 - 3)
Here 
A = 108
B = 97
x = 100
a = 8
b = -3

As per above formula the answer is = x ( x + a + b ) + ab
= 100 (100 + 8 - 3 ) - 24 = 10500 - 24 = 10476

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